Homework Answers
C6H12O6(s) + 6O2(g) ------> 6CO2(g) + 6H2O(l)
stoichiometrically, 1mole of glucose produce 6mole of H2O
mole = mass/molar mass
moles of C6H12O6 = 9.0g / 180.18g/mol = 0.04995mol
0.04995moles of glucose produce 0.2997moles of H2O
mass of H2O produced = 0.2997mol × 18.016g/mol = 5.40g
Volume of H2O produced = 5.40ml
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