Question
PLEASE INCLUDE: how inside the square root of y’+1 is opened. i will add the image for that below as well. (all my issue is with that step, please include it explained in the answer)
(1 point) Find the surface area of the sblid of revolution obtained by rotating the curve y cos(4) from x 0 torT/8 about the
1 /2mV 16 sin2(4x) +1 cos (4x)da
(1 point) Find the surface area of the sblid of revolution obtained by rotating the curve y cos(4) from x 0 torT/8 about the x-axis: -(32pi)Inl(sqrt17)+4
1 /2mV 16 sin2(4x) +1 cos (4x)da
0 0
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t- cluu 2 2 82 /6 4

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