H(Z) =(z+2)(z+0.9)/(z^2-0.01)/(z-0.5)^2(z^2-z+0.26
(42)1+ (z-0.5)z-0.9)(z-0.8) 3. The transfer function of a system is H(z) = a) Compute an analytical expression for the response y[n] if x[n] = u[n]. . Use Matlab to calculate the coefficients b) Simulate the response using Matlab (stem plot). Generate 50 points. (enter transfer function into Matlab and apply step input) (42)1+ (z-0.5)z-0.9)(z-0.8) 3. The transfer function of a system is H(z) = a) Compute an analytical expression for the response y[n] if x[n] = u[n]. . Use Matlab...
discrete-time linear system with transfer function (2) (z+2) (2-0.5)(z+0.8)(z+0.9) causal and stable. This system is possibly bota O True O False Question 8 Consider the discrete-time filter with transfer function (2) z+1 2-0.95 This filter is a high-pass filter. O True O False
By application of the impulse-invariant transformation of H (s), the following transfer functions have been obtained. Find H (s), assuming T = 0.1 s: H1(z) = 2z (z − e−0.2)(z − e−0.1) H2(z) = z − e−0.6 (z − e−0.5)(z − e−0.4) H3(z) = z (z − 0.9)(z − 0.3)
Instructor Name(s): Prof Mohamad Habli Scho Date of Exam: 26/5/2019 Time of Exam: 10:30 12:3o Invigilator(s): Prof Mohamad Habli Dura Roor Semester: Spring Acac uestions cover CLO4: 8 estion 1 en e(2+2)(z+0.9)/(z2-0.01)(z-0.5)2 (z2-z+0.26) are the values of the zeors and poles of H( Place the poles and zeros on the Z-plane. Is H(Z) stable. Instructor Name(s): Prof Mohamad Habli Scho Date of Exam: 26/5/2019 Time of Exam: 10:30 12:3o Invigilator(s): Prof Mohamad Habli Dura Roor Semester: Spring Acac uestions cover...
Which of the following filters is NOT causal: a) H(Z) = b) H(Z) = 22 Z (z–0.5)(z-2) 23 d) H(2) = (2-0.5)(2-2) c) H(Z) = (2-0.5)(2-2) e) H(Z) = (2+0.5)(2+2) g) H(2) = z[2-0.5)(2-2) z2 22(2-0.5) (2-2) Z 23 h) H(Z) = (2-1)(z-0.5)(2-2)
2. Circle the causal BIBO stable ROC below. a) 1.1<\리<1.2 b) Izk1/201zP1/2 d) 0.5<Izl<0.9 e) none above 3. A linear time-invariant IIR system is always BIBO stable a) True b) False 4. If a fiter has z-transform H(z)05, then the fiter s ;z>0.5, then the filter is zz-0.5z a) Nonlinear b)FIR )R d) two-sided e) none above 5. The discrete-time frequency o in rad/ sample of the sinusoid hin] below is d) T2 e) none above hIn] -1
Answer the following questions for a causal digital filter with the following system function H(z) 23-2+0.64z-0.64 1-1. (0.5 point) Locate the poles and zeros of H(z) on the z-plane. (sol) 1-2. (1.5 point) Sketch the magnitude spectrum, H(e i), of the filter. Find the exact values of lH(eml. IH(efr/2)I, and IH(e") , (sol) 1-3. (1 point) Relocate only one pole so that 9 s Hle)s 10 (sol) 1-4 (1 point) Take the inverse Z-transform on H(z) to find the impulse...
So, converted to a z interval, we wish to find P(0.26 < z < 0.79). Recall that since the z value is between two different values, we will need to subtract the table areas for Z, = 0.26 from the table area for z, = 0.79. Use this table to determine P(Z < 0.26) and P(Z < 0.79). Substitute these values into the formula to find the probability. (Round your answer to three decimal places.) P(0.26 < z < 0.79)...
A digital filter has the transfer function H(z) = ? -0.2 (2) Z(z - 0.7) a. Is the system stable? b. Find the output y[n] for the filter if the input is x[n] = (0.9)"u[n].
0.00 0.20 0.60 0.43 0.75 0.27 1.45 0.19 0.26 0.04 0.61 0.26 0.80 0.36 0.26 1.30 0.01 0.10 0.06 0.19 0.51 1.74 0.01 0.19 0.06 0.19 0.17 0.25 0.24 0.36 0.15 0.36 0.07 1.18 0.83 0.23 0.06 0.01 0.05 0.78 1.14 0.41 0.38 0.40 1.46 0.07 0.63 0.91 0.21 0.75 0.19 0.59 0.12 1.12 0.97 0.02 0.04 0.38 0.56 0.33 0.16 0.16 0.29 0.24 0.02 0.98 0.44 0.19 0.63 0.59 0.50 0.40 1.56 0.12 3.17 0.13 0.41 0.11 0.05 0.59...