Question

Problem 6.8 Co Dichloromethane (CH2Cl2), used as a solvent in the decaffeination of coffee beans, is prepared by reaction of methane (CH4) with chlorine. Part A How many grams of dichloromethane result from reaction of 2.07 kg of methane if the yield is 44.8 %? CH4 (g) 2C2 (g)- CH2 Cl2 ()2HCI (g) Dichloromethane Methane Chlorine VOAD m = Request Answer Submit

Answer 1

Given, reaction ini CHU(9) +2012 (9) - CH₂Cl (9) + 2H419) دولمه Imole of mellan Melbana reacte with a mole of chlorine to tovom Imole at dicuoromethane and a more of Hu, Molar masrat Cho a ix Stanic mars of Ct ux Atauic nuags 0'H' = 1X12 + 4x1= 16 9/mo Molar mass at dichloro melhane (CH2Cl2) = ix stanic mass of 'C' + 2x stanis mastod 'H't 2x Alanic mass of ci 12 +2+ 1 - 1x12 + 2x1 + 2x35.5 : 85 g/mol. Imole of City - Imole ot CaCl2 produced, 169 of meer are 85 s at CH22 Drucluced, 2070 9 of methane -> ?! Mark G Cl24 produced 2070 x 85 = 10996.875 9 = 10.996 kg

10.996 kg Of CH2 G Droduced, This encoretical yield at C aCl2 Given, J. yield = 44.8.. J. yield - Experiment d yield xloo Rheoretical yield 44.8 : xloo Experimental yield 10.965 Experimental yield: 44,8x10.996 (oo = 4.92629 = 4.9262 ks 4926.29 4926,2 got CH2 Cl2 result trau 2.09 kcs of CHy will to yield 44.8.4.