solution of the primary standard potassium hydrogen phthalate, KHC3H404, was prepared by dissolving 0.4877 g of potassi...

Question

Question

solution of the primary standard potassium hydrogen phthalate, KHC3H404, was prepared by dissolving 0.4877 g of potassium hyd

Answer 1

Answer #1

molarity of KOH = 0.1046 M

Explanation

mass KHC₈H₄O₄ = 0.4877 g

moles KHC₈H₄O₄ = (mass KHC₈H₄O₄) / (molar mass KHC₈H₄O₄)

moles KHC₈H₄O₄ = (0.4877 g) / (204.22 g/mol)

moles KHC₈H₄O₄ = 2.388 x 10^-3 mol

moles KOH = moles KHC₈H₄O₄

moles KOH = 2.388 x 10^-3 mol

concentration KOH = (moles KOH) / (volume KOH in Liter)

concentration KOH = (2.388 x 10^-3 mol) / (22.84 x 10^-3 L)

concentration KOH = 0.1046 M

Answer 2

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