Question

My Note Ak You Polymers are large molecules composed of simple units repeated many times. Thus, they often have relatively simple empirical formulas. Calculate the empirical formulas of the following polymers. (a) PVC; 38.44% C, 4.84% H, 56.73% a chemPad Help . Chemist Homewe x Wherei x + X. Xº = Greek € 7.c webassign.net/web/Stu... # @ O O O (d) polystyrene; 92.26% C, 7.74% H chemPad Help Greek (b) Lucite; 59.98% C, 8.05% H, 31.96% O chemPad Help x.x = Greek (e) Orlon; 67.90% C, 5.70% H, 26.40% N chemPad Help X.X" + Greek (c) polyethylene; 85.63% C, 14.37% H chemPad Help X.Xº = Greek

Answer 1

A (a) PVC; Given percentage of Carbon - 38.44% Then, percentage of hydrogen = 4.84% percentage of chlorine - 56073%. let, loog of pvc is taken, then the above percentages means, in loog of pve their is 38-uug of carbon, to com 4u8ug of hydrogen, 56.739 of chlorine. number of moles of c in loog of PVC = 38.14 = 3.20 moles number of moles of it in loog of PVC = 4.8y = 4.84 moles number of moles of cl in loog of pvc = 56.73 1.60 moles. divide the no. of moles values by 1.60, we get whole numbesy. no. of moles of c= 3.20 = 2 no.of moles of H = 4.8u 12 35.45 1.60 = 12 1.60 = 3 با no. of moles of ce= 1.60 1. 60 1. Emperical formula of pvc= CH₂ cel i.e, pvc = (CQ H₃ (1)

(6) Given Lucite; percentage of G= 59.98% percentage of H=8.05% Percentage of 0 = 31.96%. In a loog of compound, we have a = 59.98 9 H = 8.05g 0=31.969. Similarly, in 100 g of Lucite, no. of moles of c = r = 4.99 no of moles of H= 8.05 = 8.05 moles no. of moles of o= 31.96 1.99 to get nearest whole numbers. Divede the no. of moles values by - no of moles of C= 4.99 ~5 no of moles of H= 8.05 ~ 8 no of moles of O= 1.99 ~2 . Emperical formula of Lucite = colore C5 Og Hp) e Lucite= (C50 a ten

(c.) Given poly ethylene; percentage of C - 85.63% percentage of H= 14.37% In a 100g of polyethylene, we have 6= 85.63g H= 14.379. → in loog of polyethylene, no. of moles of c= 85.63 = 7.13 12 no. of moles of H= 14.37 - 14:37 3.56 to get nearest while divide the no. of moles values by numbers. > no. of moles of c= 7.13 = 2 no. of moles of t = 14.30 3.58 24 Emperical formula of Polyethyle - Ca Hu :. Polyethyle = (ca Hu ) n)

d) Given polystyrene ; percentage of G = 92.26% percentage of H = 7.74% In oog of polystyrene, mass of s o mass of to poor e n C = 92.20g H = 7-74g. > in loog of polystyrene, no of moles of c = 20 = 7.68 moles 8 2 no. of moles of H= 7.74 - 7.74 molen. and rounding to By dividing no. of moles values by nearest whole numbers oor we get c= 7.68 ~8 H = 7.74 ~ 8. . Emperical formula = Cq Hg. : polystyrene = (Cg H8 )

e) Given orlon, percentage of C = 67.90% percentage of H= 5.70% percentage of N= 26.40% In 100g of oolon, we have c = 67.90 g H = 5.70 g N = 26.40g. & no. of moles of c in loog of Orlon = 67.90 = 5.65 no. of moles of H= 5.70 = 5.70 no of moles of N= 26.40 - 1.88 14 by dividing the no. of moles values by 1.88 , and rounding off the values to nearest whole numbers. we get .. H = 5-10 ~ 3 N = 1.88 1.88 : Emperical formula = C₂ H₂ N Orlon= (C3H2N),