Question

For the gas phase isomerization of isopropenyl allyl ether, CH2=C(CH3)-O-CH2CH=CH2– CH3COCH2CH2CH=CH2 the rate constant has been determined at several temperatures. When In k in sis plotted against the reciprocal of the Kelvin temperature, the resulting linear plot has a slope of -1.48x104 K and a y-intercept of 26.0. The activation energy for the gas phase isomerization of isopropenyl allyl ether is kJ/mol. Submit Answer Retry Entire Group 8 more group attempts remaining

Answer 1

According to arhenius theory, expression for the rate constant is as follows: k= het Here, k is the rate constant, E, is the activation energy, and T' is the absolute temperature. In k= In A Ink = ( ) +1n y= mx + c y =-1.48*10*x+26.0 Plot of Ink ver sus 1/7 gives a straight line with a slope(m) equalto Slope of the plot = -1.48 x104 K Gas constant, R = 8.314 K-'m01-1 Slope = - -1.48x10* K=- 8.314 K-mol- 1.48*10* K= a 8.314 JK 'mol Activation energy, E, = (1.48*10* K) (8.314 JK 'mo1-1) = 1.23x10 x 15 = 123 kJ/mol mol 103 J

======================================================================

According to arhenius theory, expression for the rate constant is as follows: k= het Here, k is the rate constant, E, is the activation energy, and T' is the absolute temperature. In k= In A Ink = ( ) +1n y = mx + c y =-2.54x10*x+30.1 Plot of Ink versus 1/7 gives a straight line with a slope(m) equalto Slope of the plot = -2.54 x10* K Gas constant, R = 8.314 K-'m01-1 Slope = - -254x10^2 =-(8.3514 nor") 2.54x10' K= 8 314 JK mol Activation energy, E, = (2.54x10* K)(8.314 JK--mol-1) = 2.11x109 x 10 = 211 kJ/mol