The bonded area of stapler pin, A = 2 x (0.3 X 0.05) + 0.5 x 0.05 = 0.055 in2
(a) Let us assume Force F = 1.2 #
Shear stress = F/A = 1.2 / 0.055 = 21.81 psi
(b) Let us assume Force F = 4.8 #
Shear stress = F / A = 4.8/0.055 = 87.27 psi
A stapler works by "shearing" one staple off of a row of staples. Assume that the staple has a bonded thickness...
A stapler works by "shearing" one staple off of a row of staples. Assume that the staple has a bonded thickness of 0.05" along its edge. a. If F=R# determine the shear stress in the bond along the edge of the staple. b. If we choose to require"[요# of force to shear one of the staples, how strong (in psi) should we make the bond between the staples? 6. H-0.5 in.-I 0.3 in.