μ = 18.2
σ = 2.3
z = x - μ / σ
A)
P( 16 < X < 20)
= P(16 - 18.2/2.3 < Z < 20-18.2/2.3 )
= P(-0.96 < Z < 0.78)
= 0.3315 + 0.2823 [STANDARD NORMAL DISTRIBUTION TABLE]
= 0.6138
B)
Unacceptable sweetpeas probabality
=P(X < 14) + P(X >24)
= P(Z < 14 - 18.2/2.3) + P(Z > 24-18.2/2.3)
= P(Z < -1.83) + P(Z > 2.52)
= (0.5-0.4664) + (0.5-0.4941)
= 0.0395
Number of sweetpeas are unacceptable
= 500 x 0.0395
= 19.75
=20
the b one The length of sweet pea flower stems are normally distributed with mean 18.2 cm and standard deviation 2.3...
Woman’s heights are normally distributed with a mean of 63.8 inches and standard deviation of 2.3 inches. Find �)*. This would be the height which about 85% of woman are less than and 15% of woman are greater than.
Basketball player heights are normally distributed with a mean of 195 cm. and a standard deviation of 20 cm. What is the probability that a randomly selected player's height is less than 180 cm? Show your work.
QUESTION 5 Mean and Standard Deviation. Assume that the random variable X is normally distributed, with mean - 70 and standard deviation 8 16. Which of the following is the probability P(X <90)? (CHOOSE ONE ANSWER) (4 points) 0.8944 0.8849 0.1056 0.9015 QUESTION 6 Human Pregnancies. The lengths of pregnancies of humans are normally distributed with a mean of 268 days and a standard deviation of 15 days. Find the probability of a pregnancy lasting less than 250 days. (CHOOSE...
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 176.1-cm and a standard deviation of 2.1-cm. For shipment, 23 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is greater than 177.1-cm.P(M > 177.1-cm) =
A machine produces screws with a mean length of 1.4 cm and a standard deviation of 0.3 cm. Assuming a normal distribution, find the probabilities that a screw produced by this machine has lengths A) greater than 2.3 cm, and B) within 1.6 standard deviations of the mean. Click here to view page 1 of the table. Click here to view page 2 of the table. A) The probability that a screw is longer than 2.3 cm is (Round to...
The lengths of pregnancies are normally distributed with a mean of 269 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 308 days or longer. b. If the length of pregnancy is in the lowest 4%, then the baby is premature. Find the length that separates premature babies from those who are not premature. Click to view page 1 of the table. Click to view page 2 of the table. a. The probability...
Suppose that the walking step lengths of adult males are normally distributed with a mean of 2.4 feet and a standard deviation of 0.3 feet. A sample of 34 men’s step lengths is taken. (a) Find the probability that an individual man’s step length is less than 2.1 feet. (b) Find the probability that the mean of the sample taken is less than 2.1 feet.
A normally distributed population has a mean of 600 and a standard deviation of 60. a. Determine the probability that a random sample of size 25 selected from this population will have a sample mean less than 579. b. Determine the probability that a random sample of size 16 selected from the population will have a sample mean greater than or equal to 636.
A normally distributed population has a mean of 500 and a standard deviation of 80. a. Determine the probability that a random sample of size 25 selected from this population will have a sample mean less than 463 . b. Determine the probability that a random sample of size 16 selected from the population will have a sample mean greater than or equal to 538. A company makes windows for use in homes and commercial buildings. The standards for glass...
The lengths of adult males' hands are normally distributed with mean 189 mm and standard deviation is 7.4 mm. Suppose that 8 individuals are randomly chosen. Round all answers to 4 where possible. a. What is the distribution of ? - NG b. For the group of 8, find the probability that the average hand length is less than 191. c. Find the first quartile for the average adult male hand length for this sample size. d. For part b),...