A galvanometer has an internal resistance of 100 Ω and deflects full-scale at 2.00 mA. What size resistor should be add...
A galvanometer has an internal resistance of 100 Ω and deflects full-scale at 2.00 mA. What size resistor should be added to it to convert it to a milliammeter capable of reading up to 4.00 mA? Please explain the answer.
Homework Answers
R1 = 100 ohm
I1 = 2.00 mA
Which gives V = 2*10^-3*100 = 0.2 V
Since V will be same
Req = V/I = 0.2/0.004 = 50 ohm
So we need to 100 ohm resistor in parallel with the given resistor so that Req can be 50 ohm
Answer will be 100 ohm in parallel
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