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Heat Evolved During Combustion Consider the following reaction: 2 CO(g) + O2(g) 2 CO2(9) Use standard heats of formation from

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Answer #1

Ans :

1)

2CO + O2 = 2CO2  AH 566.OKJ

for 2 moles of CO 566.0 KJ of heat is evolved

so for 1.071 x 101 moles of CO , heat evolved will be :

= ( 1.071 x 101 mol x 566.0 KJ) / 2 mol

= 3030.93 KJ

2)

Mol CO = mass / molar mass

= (1.681 x 102 g) / 28.01 g/mol

= 6.001 mol

2 mol CO burns to evolve 566.0 KJ of heat

so 6.001 mol CO will release :

= ( 6.001 mol x 566.0 KJ) / 2 mol

= 1698.4 KJ

3)

2 mol of CO2 when formed , 566.0 kJ of heat is evolved

so when 5.112 moles of CO2 are formed , then the amount of heat evolved is :

= ( 5.112 mol x 566.0 KJ) / 2 mol

= 1446.7 KJ

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