Question

Question Help bo Triya va 32% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working mothers who do not have enough money to cover their health insurance deductibles. Complete parts (a) through (c) below. (a) Construct a binomial distribution using n=6 and p=0.32. ire Ag P(x) om X and LOL اس ام اس اما mila 5 warian 6 (Round to the nearest thousandth as needed.) 100%

Answer 1

Solution from given data: P:32). 132/100 [P=0.32) Let us Consider the binomial distribution formula is given by PLX=W=("ex) (P3* (1-P)". P(x=x) = (?) [Pit (1-0) 19- Plx=0): 166) (6-32)0 Chryny o mo 1*1* 0-09886 =0.09886 v 0.099 | P(x=0) = 0.099] 6-1 P(x=1) = 1605(0-323' (1-0.32)0* 26 ok 0-32 * 0.145393356 -0.27915 0.279 P(x-1) 50279 plx=2) :(62) (0.32.5° (1-0.3236-2 15 * 0.024 * 0.21381376 - 03284 ~ 0.328 I Pin=2) = 0.3287

0.001 0.014 0 2060 073 10 328 0.099 0279 Plx 0.001 P(-6) - 100.0 ñ t01100 01x h2oth t&t01.1 3 1* (z.914 4281 ht&to:o) *! - 3 0-1 ( 9) (29 / - (25 x 4 (210.0 =(5-*ld h10.0 ū 698100 89.0 * zehn SSE 9000 * 9. 5-9(28-0-1 ) $478:07 (557) = (s=x) d Et.0.0: hok) d Eto'o ñ ElŁ0.0 - high-0 * 958h0100 * si: h_g/75-0-1) 48280) (h2g.) = h-x)d L 902.0=1&=x)d 903.0 ñ 9909070 - = 20 * 0.032768* 0314432 P(x-3) = (by) (0.32) (1-0-32)6-3