Question

MULTIPLE CHOICE. Choose the n a tive that best completes the statement or answer the questi 1) Write the equilibri ne the equilibrium constanter ia for the following reaction in the forward direction 2CH )302)-2006) 4H2O) 2100) + 4H20 A) KICH. Op Bộ Ka-2H4 O2 [CO2+ [H2014 CO2 [H2014 2 CH4 - 31021 OK- Dj Ke-2100 H30 ICH 102P 2) Ar elevated temperatures molecular hydrogen and molecular bromine react to partially form hydrogen bromide H2(g) + Brz ( 21Br (g) A mixture of 0.682 mol of H2 and 0.410 mol of Bey is combined in a reaction vessel with a volume of 2.00 L At equilibrium at 700 K, there are 0.566 mol of H2 present. At equilibrium, there are mol of Brz present in the reaction vessel A) 0.440 B) 0.324 0.000 D) 0.566 D) 0.23 3) The equilibrium constant is equal to 5.00 at 1300 K for the reaction 2 502) Ol) - 2 SO3). If initial concentrations are SO2] -1.20 M.O2-0.45 M. and S03] 1. M. the system is A) notat equilibrium and will remain in an unequilibrated state B) notat equilibrium and will shift to the right to achieve an equilibrium state C) at equilibrium D) not at equilibrium and will shift to the left to achieve an equilibrium 4) What is true about the relationship of K and K for the reaction: 2 CH46) 3026) -2 COX) 4H2O() A) kpke B) Ky> Kc C) Kp-ke DKp and Ke are not related 5) The equilibrium constant (Kp) for the interconversion of PCs and PCI is 0.0121 PCI (8) PC (e) Cl2 (8) A vessel is charged with PCs, giving an initial pressure of 0.123 atm. At equilibrium, the partial pressure of PC atm. A) 0.078 B) 0.123 90.090 D) 0.033 E) 0.045 6) The relationship between the rate constants for the forward and reverse reactions and the equilibrium constant for the process is Keq" – A) kęks B) kg + kr C) kaks D) kq-ks E) krk
Just give me the answers

Answer 1

1. The equilibrium constant expression for the reaction

2CH(g) + 302(g) = 2CO(g) + 4H2O(g)
is

C)
Ke= COH2014 (CH4)2 [0213

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2. Answer:- B) 0.324 mol

The reaction is
H2(g) + Br2(g) = 2H Brg)

Initial mol of H₂ = 0.682

mole of H₂ at equilibrium = 0.566 mol

ie. mol of H₂ reacted = (0.682 - 0.566) = 0.116 mol

Initial moles of Br₂ = 0.440 mol

from reaction it is clear that H₂ and Br₂ reacts in 1:1 ratio.

therefore, moles of Br₂ reacted = 0.116 mol

and

equilibrium moles of Br₂ = (0.440 - 0.116) = 0.324 mol

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3) Answer :- C) at equilibrium

The given reaction
2.5O2(g) + O2(g) = 2.503(g)

K_c = 5

SO2) = 1.2M
  
02] = 0.45M
  
SO3 = 1.8M
  

Now,

(S0312 Qc = [S02][02] (1.8) (1.2)(0.45)

i.e Q_c = K_c ie. systemis at equilibrium.

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4) Answer :- B) K_p> K_c

The given reaction is

2CH(g) + 302(g) = 2CO(g) + 4H2O(g)

We know
K, = K(RT)In

now,
An = (molesof product – molesofreactant)

from reaction
An = ((2+4) - (2+3) = 1

therfore,
K, = K (RT) = K (RT)

ie. K_p > K_c

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5) Answer :- D) 0.033

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6) Answer:- C)
KOK