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6. Terbium-152 is a positron emitter with a half-life of 18.0 hours. How long would take for the activity in a sample of this
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In (SA) = kt a time t At initial concentration At concentration after k is rate constant K = 0.693 It is the half-life. InCAwloo 0.693 18hr | (+) x 18 km 0.693 t= 25.426 hours = 25.5 hours. - A = 0.6CA.. CAO T. 0.693 0.6CA 5730 years rs tx In low) x

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step by step please! need help understanding 6. Terbium-152 is a positron emitter with a half-life of 18.0 hours. Ho...
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