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Question 15 Type numbers in the boxes. Find the p-value for the hypothesis test. A random sample of size 54 is taken. The sam

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Answer #1

Solution :

Q 15)

This is the two tailed test .

The null and alternative hypothesis is ,

H0 :  \mu = 400

Ha : \mu \neq 400

Test statistic = z

= (\bar x - \mu) / \sigma / \sqrtn

= (426 - 400) /80 / \sqrt54

Test statistic = 2.39

P(z > 2.39) = 2 * [1 - P(z < 2.39)] = 2 * 0.0084‬

P-value = 0.0168‬

Q 16)

Solution :

This is the one tailed test .

The null and alternative hypothesis is ,

H0 :  \mu = 14

Ha : \mu > 14

Test statistic = z

= (\bar x - \mu) / \sigma / \sqrtn

= (16.3 - 14) / 5.9 / \sqrt45

Test statistic = 2.62

P(z > 2.62) = 1 - P(z < 2.62) = 1 - 0.9956

P-value = 0.0044‬

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