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2. You will use a weighted amount of KHP (a weak acid) to standardize your ~ 0.2 M NaOH solution. Assuming that you...
1. Calculate how many milliliters (mL) of 2 M NaOH will be needed to make 0.50 L of a 0.2 M aqueous NaOH solution....
1. Calculate how many milliliters (mL) of 2 M NaOH will be needed to make 0.50 L of a 0.2 M aqueous NaOH solution. 2. You will use a weighted amount of KHP (a weak acid) to standardize your ~ 0.2 M NaOH solution. Assuming that you made exactly 0.2 M NaOH, calculate how many grams of KHP will react with exactly 15 mL of 0.2 M NaOH. Use the information below to help answer this question: _C02 K+ CO2...
As part of Lab 11 you will make and standardize a solution of NaOH(aq). Suppose in the lab you measure the solid NaOH an...
As part of Lab 11 you will make and standardize a solution of NaOH(aq). Suppose in the lab you measure the solid NaOH and dissolve it into 100.0 mL of water. You then measure 0.1993 g of KHP (204.22 g/mol) and place it in a clean, dry 100-mL beaker, and then dissolve the KHP in about 25 mL of water and add a couple of drops of phenolphthalein indicator. You titrate this with your NaOH(aq) solution and find that the...
(Answer from question 4) HP− + H2O is in equilibrium with P2− + H3O+ This axid...
(Answer from question 4) HP− + H2O is in equilibrium with P2− + H3O+ This axid will attack the base Assume 1 mol of KHP will neutralize 1 mol of NaOH V = 25 ml M = 0.1M Mol Acid = mol Base Mol base = M*V = 25 ml ^0.1 M = 2.5 mmol of base therefore, you need 2.5 *10^-3 mol of acid, that is mol of KHP Since KHP = 204.22 g/gmol mass = mol*MW = 2.5*10^-3...
In your Analysis of Carboxylic Acids you prepared and calibrated the NaOH (Mw 40.00 g/mol) solution...
In your Analysis of Carboxylic Acids you prepared and calibrated the NaOH (Mw 40.00 g/mol) solution with Potassium Acid Phthlate (KHP MW 204.22 g/mol). You weighed 2.4 g of NaOH and added it to 400. ml of DI to prepare the NaOH solution. You then calibrated the NaOH solution by titrating it against KHP. If you used 1.0702 g of KHP and titrated it with the NaOH solution (See Photos Below of the start and end burette reading), what was...
50.0 mL sample of the weak acid the concentration of the weak acid = 0.15 M...
50.0 mL sample of the weak acid
the concentration of the weak acid = 0.15 M
25 mL of the week acid into 100 mL beaker
titrated this solution of 0.21 M NaOH
moles of weak acid = 3.75*10^-3
moles of NaOH = moles of week acid
c) How many milliliters of the NaOH are required to neutralize the sample of weak acid? d) How many moles of NaOH have been added at one half of the volume in part...
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
2. Calculate the mass of KHP needed to react completely with 15 mL of a 0.10 M NaOH solution. Consider the reaction...
2. Calculate the mass of KHP needed to react completely with 15 mL of a 0.10 M NaOH solution. Consider the reaction equation to be as shown below, molar mass of KHP is 204.3g/mol 3. Calculate the molarity of a solution of sodium hydroxide if 23.64 mL of this solution is needed to neutralize 0.5632 g of KHP. 4. It is found that 24.68 mL of 0.1165 M NaOH is needed to titrate 0.2931 g of unknown monoprotic acid to...
I MAINLY NEED HELP ON TABLES PLS HELP THANK YOU Materials: NaOH MW = 40 g/mL,...
I MAINLY NEED HELP ON TABLES
PLS HELP THANK YOU
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC2H4O4, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 mL water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the...
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
309 Week One Data and Calculations Standardization of NaOH Solution Sample 1 Sample 2 Sample 3...
309 Week One Data and Calculations Standardization of NaOH Solution Sample 1 Sample 2 Sample 3 Mass of KHP 10.5749 10.8939 1.26g. Initial Volume NaOH, V. (mL) Read to nearest 0.01 ml. No.25mL 8.86 m L 10.45 mL Final Volume NaOH, V:(mL) 0.31 ml 25.73 m2 Read to nearest 0.01 mL 24.47 ml Total Volume NaOH used mL) 110.62 mL 16.92 mL 24.03 mL Moles KHP 2.81 × 10-3 4.37x10-3 6.16 x 10 3 Moles NaOH 12.81x 10-3 4.37 ×...
1. Calculate how many milliliters (mL) of 2 M NaOH will be needed to make 0.50 L of a 0.2 M aqueous NaOH solution. 2. You will use a weighted amount of KHP (a weak acid) to standardize your ~ 0.2 M NaOH solution. Assuming that you made exactly 0.2 M NaOH, calculate how many grams of KHP will react with exactly 15 mL of 0.2 M NaOH. Use the information below to help answer this question: _C02 K+ CO2...
In your Analysis of Carboxylic Acids you prepared and calibrated the NaOH (Mw 40.00 g/mol) solution with Potassium Acid Phthlate (KHP MW 204.22 g/mol). You weighed 2.4 g of NaOH and added it to 400. ml of DI to prepare the NaOH solution. You then calibrated the NaOH solution by titrating it against KHP. If you used 1.0702 g of KHP and titrated it with the NaOH solution (See Photos Below of the start and end burette reading), what was...
50.0 mL sample of the weak acid
the concentration of the weak acid = 0.15 M
25 mL of the week acid into 100 mL beaker
titrated this solution of 0.21 M NaOH
moles of weak acid = 3.75*10^-3
moles of NaOH = moles of week acid
c) How many milliliters of the NaOH are required to neutralize the sample of weak acid? d) How many moles of NaOH have been added at one half of the volume in part...
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
2. Calculate the mass of KHP needed to react completely with 15 mL of a 0.10 M NaOH solution. Consider the reaction equation to be as shown below, molar mass of KHP is 204.3g/mol 3. Calculate the molarity of a solution of sodium hydroxide if 23.64 mL of this solution is needed to neutralize 0.5632 g of KHP. 4. It is found that 24.68 mL of 0.1165 M NaOH is needed to titrate 0.2931 g of unknown monoprotic acid to...
I MAINLY NEED HELP ON TABLES
PLS HELP THANK YOU
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC2H4O4, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 mL water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the...
Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...
309 Week One Data and Calculations Standardization of NaOH Solution Sample 1 Sample 2 Sample 3 Mass of KHP 10.5749 10.8939 1.26g. Initial Volume NaOH, V. (mL) Read to nearest 0.01 ml. No.25mL 8.86 m L 10.45 mL Final Volume NaOH, V:(mL) 0.31 ml 25.73 m2 Read to nearest 0.01 mL 24.47 ml Total Volume NaOH used mL) 110.62 mL 16.92 mL 24.03 mL Moles KHP 2.81 × 10-3 4.37x10-3 6.16 x 10 3 Moles NaOH 12.81x 10-3 4.37 ×...
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