Question

A researcher studying the nutritional value of a new candy places a 4.40 g sample of the candy inside a bomb calorimeter and
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Answer #1

Given:
C = 43.40 KJ/K = 43.40 KJ/oC
delta T = 43.40 oC

Energy released,
Q = Ccal*delta T
= 43.40 KJ/oC * 43.40 oC
= 100.688 KJ

1 nutritional calorie = 4.184 KJ

Converting this energy to nutritional calorie

Q = 100.688 KJ / 4.184 KJ/Cal
= 24.065 Cal

This is for 4.40 g

so,
nutritional calorie per gram = 24.065 Cal/4.40 g
= 5.47 Cal/g

Answer: 5.47 Cal/g

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