The compressive strength of samples of cement can be modeled by a normal distribution with a mean of 6000 kilograms per square centimeter and a standar deviation of 100 kilograms per square centimeter
c) what strength is exceeded by 95% of the samples?
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7000 hours and a standar deviation of 600 hours
a) what is the probability that a laser fails before 5000 hours?
Suppose that the timeto failure in hours of fans in a personal computer can be modeled by and exponential distribution with landa=0.0003
b) what proportion of the fans will last at most 7000 hours
Solution:
c)
Given that
mean of 6000 kilograms
standard deviation of 100 kilograms
strength is exceeded by 95% of the samples
0.95 = P( Z > x - 6000 / 100) = 1 - (x - 6000 / 100)
x - 6000 / 100 = 0.05
using tables we get
x - 6000 / 100 = -1.645
x = 5835.5 = 5835
a) Given that
mean of 7000 hours
standard deviation of 600 hours
probability that a laser fails before 5000 hours
P( X < 5000) = P( Z < 5000 - 7000 / 600)
=P( Z< -3.33)
Using standard normal table
1−P ( Z<3.33 )=1−0.9996=0.00039
b)
Let X be exponnetial distributed normal variable
λ = 0.0003
proportion of the fans will last at most 7000 hours
The compressive strength of samples of cement can be modeled by a normal distribution with a mean of 6000 kilograms per...
The life of a semiconductor laser at a constant power can be modeled by a Weibull distribution with a mean of 7000 hours and a standard deviation of 600 hours. (a) What is the probability that a laser fails before 5800 hours? (b) What is the life in hours that 90% of the lasers exceed? (c) What should the mean life equal in order for 99% of the lasers to exceed 10,000 hours before failure? (d) A product contains three...