The value of In(2) can be obtained by an alyzing the series 1)1 72 1. Does this series give a number? 2. With the previ...
16) Approximate the definite integral using power series. If the antiderivative obtained is an alternating series, use the Alternating Series Estimation Theorem to ensure the error is less than 0.001; otherwise, use at least four nonzero terms to approximate the integral. (a) { er at 6) ſ'cos(x) dx
Let Pbé à pósitive, continuous, and decreasing function for x 2 1, such that an-n). If the series an n 1 converges to S, then the remainder RN -S-Sw is bounded by Use the result above to approximate the sum of the convergent series using the indicated number of terms. (Round your answers to four decimal place Σ ,T, ten terms n2 +1' Include an estimate of the maximum error for your approximation. (Give your answer to four decimal places.)...
3) Later in this course, we will learn that the function, arctan x, is equivalent to a power series for x on the interval -1sxs: 2n+1 (-1)" arctan x = We can use this power series to approximate the constant π . a) First, evaluate arctan1). (You do not need the series to evaluate it.) b) Use your answer from part (a) and the power series above to find a series representation for (The answer will be just a series-not...
Consider the series (+2) ".value Consider the series ( 5n3 +1 | 4n3 + 3 ) . Evaluate the the following limit. If it is infinite, type "infinity" or "inf". If it does not exist, type "DNE". lim vlanl = Answer: L= What can you say about the series using the Root Test? Answer "Convergent", "Divergent", or "Inconclusive". Answer: choose one Determine whether the series is absolutely convergent, conditionally convergent, or divergent. Answer "Absolutely Convergent", "Conditionally Convergent", or "Divergent". Answer:...
(1 point) What is the least number of terms of the series that we need to add in order to approximate the sum to within 0,003 of the actual sum of the series? (-1)"-1 n2 n 1 ISum - Sk Slak+1|| Recall that for an alternating series: error number of terms: N (Don't forget to enter the smallest possible integer.) approximation of sum: S (1 point) What is the least number of terms of the series that we need to...
5) Suppose -1 an is a conditionally convergent series and let L E IR be arbitrary. Give an informal justification for each of the following. a. We can add up positive terms first, until the first time the sum is greater than L. Then we can add negative terms until the first time the resulting sum is less than L again. Moreover, we can always repeat this process. In repeating the process described in part a, at some point, each...
5. B and C is convergent, expressing your answer in in- terval notation. 1. (-0,0) 006 10.0 points Determine all values of p for which the series 2. p = {0} MP In m 3. 0.00) converges. 1. p > 2 4. (-0,00) 5. (0,0) AV V 009 10.0 points Determine whether the series 5. p < -2 § (-1)-1sin (1) 6. p > 1 is absolutely convergent, conditionally con- vergent or divergent 007 10.0 points Find the smallest number...
(1 pt) Test each of the following series for convergence by either the Comparison Test or the Limit Comparison Test. If either test can be applied to the series, enter CONV if it converges or DIV If it diverges. If neither test can be applied to the series, enter NA. (Note: this means that even if you know a given series converges by some other test, but the comparison tests cannot be applied to it, then you must enter NA...
Problem 3. Consider the series: 1 n [ln (n)]4 n=2 a) (6 pts) Use the integral test to show that the above series is convergent. b) (4 pts) How many terms do we need to add to approximate the sum within Error < 0.0004.
1. Give an example of a convergent infinite series whose sum equals 1 Show that your series converges and show how to finds its sum (i.e. verify that the sum equals what we want). There are infinitely many possible answers! 2. n=1 3n2 – 2 (-1)" 4n5/2 + n a. Determine whether n=1 converges or diverges. 3n2 – 2 3n2 – 2 (-1)" 4n5/2 + n 4n5/2 +n b. Determine whether n=1 converges or diverges. 3n2 – 2 (-1)" 4n5/2...