Question

B. Molar Concentration of an Acid Solution Acid type HA HA HA Unknown No. Balanced equation for beutralization of acid with NaOH. 25.0 25.0 25.0 1. Volume of acid solution (m) 2 Buret reading of NaOH, initial (L.) 3. Buret reading of NaOH,final (mL) 4. Volume of NaOH dispensed (m) 5. Molar concentration of NaOH (MOVL). Part A 6. Moles of NaOH dispensed (mol) 7. Molar concentration of acid solution (mol/L) Data Analysis, 8. Average molar concentration of acid solution (MOL) Data Analysis, 9. Standard deviation of molar concentration Data Analysis, D 10. Relative standard deviation of molar concentration (RSD) Laboratory Questions Circle the questions that have been assigned. m h em that is used for the standardization of the sodium hydroxide solution. Suppose o

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molar concentration of NaOH solution is 0. 128

Answer 1

Answer:

Given NaOH = 0.128 M and acid is monoprotic (HA).

For the calculation of molarity of acid: V_HA.M_HA = V_NaOH.M_NaOH

M = Molarity and V = Volume

	Sample 1	Sample 2	Sample 3
Moles of NaOH	1.984 x 10-3	1.920 x 10-3	1.907 x 10-3
Molar concentration of acid (mol/L or M)	0.07936	0.07680	0.07688

Average molarity = (0.07936 + 0.07680 + 0.07688)/3 = 0.07768 M { Mean }

Standard Deviation

a₁ = (0.07936 - 0.07768)² = 2.822 x 10^-6

a₂ = (0.07680 - 0.07768)² = 7.744 x 10^-7

a₃ = (0.07688 - 0.07768)² = 6.400 x 10^-7

a₁ + a₂ + a₃ = 4.2368 x 10^-6

Variance (population method) = (a₁ + a₂ + a₃)/3 = 1.4122 x 10^-6

Variance (sample method) = (a₁ + a₂ + a₃)/2 = 2.1184 x 10^-6

S.D (population method) = 1.1884 x 10^-3

S.D (sample method) = 1.4554 x 10^-3

Relative S.D { (S.D/mean) x 100 }

Relative S.D (population method) = 1.53 %

Relative S.D (sample method) = 1.87 %

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