Question

A gas is compressed from an initial volume of 5.75L to a final volume of 1.24 L by an external pressure of 1.00 ATM...

A gas is compressed from an initial volume of 5.75L to a final volume of 1.24 L by an external pressure of 1.00 ATM. During the compression the gas releases 125 J of heat.  What is the change in internal energy of the gas?
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Answer #1
Concepts and reason

The expansion or compression of gas can takes place in a reversible or in an irreversible manner based on the conditions used. An irreversible process may occur when internal pressure(P)
int
is greater than external pressure(P)
ext
because, the system does not attain equilibrium at every stage of the process.

Fundamentals

Pressure-volume work:

Irreversible process: In this process, in
ext
and the expansion of gas take place rapidly without maintaining equilibrium in the surroundings. Therefore, the pressure-volume (PV)
work done against the constant external pressure is given below:

W -PAV
ext

Where,
The work done by the gas is W
The external pressure is P,
ext
The internal pressure is P
The change in the volume is A

First law of thermodynamics:The first law of thermodynamics is defined as the change in internal energy of a system,which is equal to the heat supplied to the system added to the work done on the system.

AU q+w

Here

The change in internal energy is AU.
The heat added to the system is q.
The work done on the system is w

Given data:

External pressure, Pt = 1.00 atm
Initial volume, V =5.75L
Final volume, V = 1.24L
heat, q 125J

Work done ‘W’ is calculated below:

W -PAV
=-Pe (Va-
=(1.0atm)1.24-5.75)L
ext
fialV
initial
cxt
- 4.51 L atm

Convert the units for work done from L atm
tojoules
.

ILatm 0.101325 kJ
W = 4.51L atm x 101.33J
Latm
W =456.998J

AU q+W
Substitute -125 J for q and 456.998 J for W.
AU 125 J+456.998 J
AU 331.998 J.

Ans:

The internal energy change of the gas is331.998 J
.

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