The expansion or compression of gas can takes place in a reversible or in an irreversible manner based on the conditions used. An irreversible process may occur when internal pressure is greater than external pressure because, the system does not attain equilibrium at every stage of the process.
Pressure-volume work:
Irreversible process: In this process, and the expansion of gas take place rapidly without maintaining equilibrium in the surroundings. Therefore, the pressure-volume work done against the constant external pressure is given below:
First law of thermodynamics:The first law of thermodynamics is defined as the change in internal energy of a system,which is equal to the heat supplied to the system added to the work done on the system.
Here
Given data:
Work done ‘W’ is calculated below:
Convert the units for work done from to.
Ans:The internal energy change of the gas is.
A gas is compressed from an initial volume of 5.75L to a final volume of 1.24 L by an external pressure of 1.00 ATM...
A gas is compressed from an initial volume of 5.75L to a final volume of 1.24 L by an external pressure of 1.00 ATM. During the compression the gas releases 125 J of heat. What is the change in internal energy of the gas?
A gas is compressed from an initial volume of 5.40 L to a final volume of 1.24 L by an external pressure of 1.00 atm. During the compression the gas releases 120 J of heat. What is the change in internal energy of the gas?
A gas is compressed from an initial volume of 5.50 L to a final volume of 1.22 L by an external pressure of 1.00 atm . During the compression the gas releases 123 J of heat. What is the change in internal energy of the gas?
A gas is compressed from an initial volume of 5.35 L to a final volume of 1.21 L by an external pressure of 1.00 atm. During the compression the gas releases 120 J of heat. Part A You may want to reference (Pages 265-266) Section 6.5 while completing this problem. What is the change in internal energy of the gas? Express your answer to three significant figures. VO AED ? AE= Submit Request Answer
MISSED THIS? Read Section 7.4 (Pages 272-278). A gas is compressed from an initial volume of 5.45 L to a final volume of 1.24 L by an external pressure of 1.00 atm. During the compression the gas releases 124 J of heat. Part A What is the change in internal energy of the gas? Express your answer to three significant figures. VOAESD ΔΕ- Request Answer Submit Provide Feedback
1. A gas is compressed from an initial volume of 5.35 L to a final volume of 1.23 L by an external pressure of 1.00 atm. During the compression the gas releases 124 J of heat. What is the change in internal energy of the gas? 2. Calculate ΔHrxn for the following reaction: CaO(s)+CO2(g)→CaCO3(s) Use the following reactions and given ΔH values: Ca(s)+CO2(g)+12O2(g)→CaCO3(s), ΔH= -812.8 kJ 2Ca(s)+O2(g)→2CaO(s), ΔH= -1269.8 kJ
A gas is compressed from an initial volume of 5.40L to a final volume of 1.20L by an external pressure of 1.00 atm . During the compression the gas releases 125J of heat. What mass of natural gas (CH 4 ) must you burn to emit 264kJ of heat? CH 4 (g)+2O 2 (g)?CO 2 (g)+2H 2 O(g) ?H ? rxn =?802.3kJ
An external pressure of 2.00 atm causes a gas to compress by 20.0 L. In the process of compression, the gas releases 1200 J of heat to the surroundings. What is the change of the internal energy of this gas? 1 atm = 101325 Pa, 1 L = 0.001 m3 .
1)A gas is compressed at a constant pressure of 0.800 atm from 8.00 L to 1.00 L. In the process, 410 J of energy leaves the gas by heat. (a) What is the work done on the gas? J (b) What is the change in its internal energy? J 2) A gas increases in pressure from 2.00 atm to 6.00 atm at a constant volume of 1.00 m3 and then expands at constant pressure to a volume of 3.00 m3...
An external pressure of 4.00 atm causes a gas to compress by 10.0 L. In the process of compression, the gas releases 1200 J of heat to the surroundings. What is the change of the internal energy of this gas? 1 atm = 101325 Pa, 1 L = 0.001 m . (A) +5253 J (B) +2853 J (C) −1605 J (D) −2853 J (E) −5253 J