Question

the Ka of a nonprotic weak acid is .00419. what is the percent ionization of a .185 M solution of this acid?

© Assignment 2700/2800 Resources Ex Give Up? Feedback Try Again Score: < Question 19 of 28 > Attempt 5 The K, of a monoprotic weak acid is 0.00419. What is the percent ioniza < Feedback percent ionization: 46.5 percent ionization: 46.5 The chemical equation for the ionization of a monoprotic weak acid is HA(aq) = H(aq) + A™(aq) and the ionization constant is defined as [H ][A") [HA] Percent ionization is defined as [HJequilit percent ionization = = [HAlinit terms privacy policy tus help

Answer 1

MAla (aa) A (a) Ka b.Do419 Ka = CHA) 6.185 0.185-2 0.00419 To.185- D.00419 D.185- 0-125 [0185

(0.00419)(0.185) 0.000775 2 J 0.000775 0. D278 Mmote Nouw Towigaton foid that disouats auital moles o auel Motes lo0/ CUAJ o.0278 0.185 0.1S02x 10 17 1cent loigaten :I5 Awswer