At boiling point , Vapor pressure (P1) = 1 atm.
Boiling point (T1) = 76.7 + 273 = 349.7 K
at , T2 = 15.8+273 = 288.8 K , vapor pressure (P2) = 0.0987 atm
Clausius clapyeron equation is
ln( ) = ×
Or, ln ( ) = × (
Or, 2.325 = × (0.00346 - 0.00286)
Or, 2.315 = × 0.0006
Or, = (2.315/0.0006)
Or, = 3858
Or, = 3858× R
Or, = 3858×8.314
Or, = 32078Jmol-1
Or, = 32.078 KJ mol-1
Hence, calculated enthalpy of vaporisation is more close to 31.9 KJ/mole.
Therefore calculated result supports that enthalpy od vaporisation is 31.9 KJ mol-1
[ R = 8.314 J mol-1 K-1]
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