Question

Write down the chemical equation for the 2nd ionization (IE2) energy for calcium. Follow the instructions below:

Calculate IE2 for calcium using the data listed below. For each data item, write down the chemical equation associated with the process (i.e., that defines the process) - making sure to indicate all phases. In order to show your work, demonstrate, using Hess' law, how you came up with the Born-Haber cycle that lead to the net chemical equation for the IE2 of calcium. Report the final value in kJ/mol. 1) Bond dissociation energy of gaseous molecular fluorine = 158 kJ/mol F - 21 2) First ionization energy of Ca = 589.8 kJ/mol Cal Care 3) Heat of sublimation of calcium = 178.2 kJ/mol -Same things CE 4) Electron affinity for fluorine = -328 kJ/mol Etc te 5) Lattice energy of Cafz(s) =-2630 kJ/mol 6) Enthalpy of formation of CaFz(s) = -1215 kJ/mol

Answer 1

" Bond dissocialion energy of gaseous molecular fluorine F2(g) →→ 26 (g) a. First ionization of ca (8) - SHIE AHR 158 kifort Ca Cat - s%22+ 4 DE, - 589.8 / ghel le mot sub = 178.2 k3 May 3. hear of sublimation - Ca(s) caca 4. Electron affinity of fluorine 26°C) &EAL 26–9) g. Lattice enery of cah far as a alam AEA, = -328 67/mol AEA, = 2x1-328) = 656 kilot <U>-263063/wert/ ço 2863) > Cafe E. Enthalpleo ly q formation of catz Born _cycle ./215 kJ mol + 20 - 4H formation Caf(s) CAB) 4HSub a 5 10 2x EALF- 2F8) 1* TEL Au (lattial energy) Categy tha By hess's Law [change in enthalpy is same cirespet 4H formation = 4 Hsub + STE+2nd Je + Disociation -28EA -?215 kJ/mol = 178.2 kJ/mol + 589.3 kJ brot +76, + 158 kJ/mo + Disociahon 2£A + (laties energy 8 kJpmol + 25 + 158 kJ/mol +2X(-928) tort + - 2630 kJ/mol. -1215 ks/mot: 926 kJ/mol + i£, - 3286 kJ/mol (1215 +3286-926) kJ/mol = If CS Scan 14 Sith kJ/mol > IE, Ans CamScattet