What is the work associated with decomposition of trinitrotoluene (TNT) upon detonation according to the following reaction at 300.15 K? C7H5N3O6(s)⟶3/2 N2(g)+5/2 H2(g)+3O2(g)+7C(s) Express your answer using four significant figures. (Answer must be in kJ/mol)
1 mole C7H5N3O6 gives 3/2 moles N2 and 5/2 moles H2 and 3 moles O2 gas
Total gas moles produced = N2 moles + H2 moles + O2 moles
= 1.5 + 2.5 + 3 = 7
work done = - P x dV where dV is change in volume
we use ideal gas equation PV = nRT ( since V is nothing but volume occupied by all gases)
work done = - nRT where R = gas constant = 0.08206 liter atm/molK
= - 7 mol x 0.08206 liter atm/molK x 300.15 K
= - 172.412 atm liter /mol
we have 1 atmliter = 101.325 J
hence work done = - 172.412 atm liter /mol x ( 101.325 J/atmliter)
= - 17470 J/mol
= - 17.47 KJ/mol
( -ve sign indicates expansion work )
What is the work associated with decomposition of trinitrotoluene (TNT) upon detonation according to the following rea...
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