Question

How many moles of aluminum are required to completely react with 107 mL of 6.00 M H₂SO₄ according to the balanced chemical reaction: 

2 Al(s) + 3 H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 3 H₂(g)

How many moles of AgI will be formed when 75.0 ml of 0.300 M AgNO₃ completely reacted according to the balanced chemical reaction: 

2 AgNO₃(aq) + Cal₂(aq) + 2 Agl(s) + Ca(NO₃)₂(aq)

Answer 1

Answer 2

Answer 3

Ans. Mole of AgNO_​​​3 = molarity × volume (L)

Mole of AgNO_​​​3 = 0.300 × 75/1000 = 2.25 × 10^-2 mol

According to balanced reaction

2 Mole of AgNO_​​​3 produced Agl = 2 mole

2.25 × 10^-2 mol AgNO_​​​3 produced Agl = (2/2) × 2.25 × 10^-2 = 0.0225 mol