Homework Answers
The given process is condensation process and heat energy is during the process
heat lost by water = n*DHcondensation + m*s*DT
= (16.50/18)*(-40.7*1000) + 16.50*4.184*(13.50-100)
= -43279.94 J = -43.279 J
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Il See Periodic Table See Hint Calculate the change in heat when 13.00 g of water vapor (steam) at 100.0°C condenses to liquid water and then cools to 10.50 °C.
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