A
collapsible plastic bag (figure below) contains a glucose solution.
If the average gauge pressure in the vein is 1.29 103
Pa,
what must be the minimum height h
of
the bag in order to infuse glucose into the vein? Assume the
specific gravity of the solution is 1.05.
h
=
m
P = pgh where P = pressure, p = density of solution, g = 9.81m/s^2,
and h = height
Here, p = 1.05*1000kg/m^3 = 1050kg/m^3
h = P/pg = 1.29 x 10^3 N/m^2 / [(1050kg/m^3)*9.81m/s^2] =
0.125m
A collapsible plastic bag (figure below) contains a glucose solution. If the average gauge pressure in the vein is 1.2...
A collapsible plastic bag (figure below) contains a glucose solution. If the average gauge pressure in the vein is 1.23 times 10^3 Pa, what must be the minimum height h of the bag in order to infuse glucose into the vein? Assume the specific gravity of the solution is 1.04.
A collapsible plastic bag (see figure below) contains a glucose solution. If the average gauge pressure in the artery is 1.31E+4 Pa, what must be the minimum height, h of the bag in order to infuse glucose into the artery? Assume that the specific gravity of the solution is 1.06.
4. (-/1 Points) DETAILS SERCP11 9.4.P.011. MY NOTES ASK YOUR TEACHER A collapsible plastic bag (figure below) contains a glucose solution. If the average gauge pressure in the vein is 1.37 x 103 Pa, what must be the minimum height h of the bag in order to infuse glucose into the vein? Assume the specific gravity of the solution is 1.03. h = m Glucose solution
If the average gauge pressure in the artery is 1.37E+4 Pa, what must be the minimum height, h of the bag in order to infuse glucose into the artery? Assume that the specific gravity of the solution is 1.02.
2. A liquid medicine is injected into a patient from an IV bag elevated h = 0.800 m above the needle, see figure. The needle is placed horizontally. The needle is 3.00 cm in length and 0.400 mm in diameter. Assume the average gauge pressure inside the vein is 1.28 103 Pa; the viscosity of the medicine is 2.00 103 Pas; and the density of the medicine is 1.05 103 kg/m3. (1) Calculate the pressure difference between the...
A liquid medicine is injected into a patient from an IV bag elevated h = 0.800 m above the needle, see figure. The needle is placed horizontally. The needle is 3.00 cm in length and 0.400 mm in diameter. Assume the average gauge pressure inside the vein is 1.28 x 10^3 Pa; the viscosity of the medicine is 2.00 x 10^-3 Pa*s; and the density of the medicine is 1.05 x 10^3 kg/m^3 . (1) Calculate the pressure difference between...
A liquid medicine is injected into a patient from an IV bag elevated h-0.800 m above the needle, see figure. The needle is placed horizontally. The needle is 3.00 cm in length and 0.400 mm in diameter. Assume the average gauge pressure inside the vein is 1.28 x 103 Pa; the viscosity of the medicine is 2.00 10-3 Pa-s; and the density of the medicine is 1.05x 103 kg/m. (1) Calculate the pressure difference between the input and output of...
Can't figure out the concentration of the complex of solns. 10, 11, 12, 13, & 14. Modern Experimental Chemistry Chemistry 153 The Iron(III) Thiocyanate Complex Purpose of the Experiment To determine the chemical formula of a complex ion and measure its formation equilibrium constant Equipment Spectro Vis spectrophotometer and LabQuest, cuvette, 25-mL buret (3), ring stand, buret clamp (2), 50-mL beaker (3), small plastic beakers Reagents SCN, as KSCN, 0.00200 M solution Fe; as Fe(NO), 0.00200 M solution and a...
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