Question

5 points) What are the frequency. V. and photon ene wavelength of 337.1 nm? and photon energy. E. of light having a

Answer 1

Given value is

wavelength $\lambda$ = 337.1 nm

we know that

1 nm = 1 $\times$ 10^-9 m

hence

wavelength $\lambda$ = 337.1 $\times$ 10^-9 m

c = speed of light = 3.0  $\times$ 10⁸ m/s

We know the formula

Frequency = speed of light / wavelength

then

Frequency = 3.0  $\times$ 10⁸ m/s / 337.1 $\times$ 10^-9 m = 8.90 $\times$ 10¹⁴ s^-1 = 8.90 $\times$ 10¹⁴ Hz

Frequency = 8.9 $\times$ 10¹⁴ Hz

Now

Photon energy

E = hc / $\lambda$

where h = plancks constant = 6.626 $\times$ 10^-34 J.s

So

Energy = 6.626 $\times$ 10^-34 J.s $\times$ 3.0  $\times$ 10⁸ m/s / 337.1 $\times$ 10^-9 m = 5.90 $\times$ 10^-17 J

Photon energy = 5.90 $\times$ 10^-17 J