Question

Find the speed of an electron that has a kinetic energy of 2.07 eV. 1 eV= 1.602 x 10^-19 J. Answer in units of m/s.

Calculate the speed of a proton with a kinetic energy of 2.07 eV. Answer in units of m/s.

A parallel-plate capacitor has a capacitance Co. A second parallel-plate capacitor has plates with twice the area and twice the separation. What is the capacitance of the second capacitor?

Calculate the energy stored in a 27.3 uF capacitor when it is charge to a potential of 82 V. Answer in units of mJ.

Two parallel conducting plates separated by a distance d are connected to a battery of voltage E. What is correct if the plate separation is doubled while the battery remains connected?

001 (part 1 of 2) 10.0 points Find the speed of an electron that has a kinetic energy of 2.07 eV. 1 eV 1.602 x 10-19 J. Answer in units of m/s. 002 (part 2 of 2) 10.0 points Calculate the speed of a proton with a kinetic energy of 2.07 eV. Answer in units of m/s.

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Answer #1

The speed of the electron can be calculated as follow The mass of electron ism,=9.11x10-ng thegi iven KE 2.07 eV #207x 1.602x10 fom 1ev-1.602x10-°J] 2.07x 1.602x 10,--x3.1 1x10 2.07x1.602x1019 x2 6.632x10-19 x10 0.728x10 9.11x10- 9.11 ?. =0728x102 = 0.853x 10° = 8.53x10 m/s(2) The speed of the proton can be calculated as follow The mass of proton is m,-1672x10 kg the given K.E-207ev -2.07x1.602x1

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