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The following questions A24 - A26 relate to 100 ml of 0.0150 M solution of benzoic acid (C6H3COOH). K.(C6H3COOH) = 6.4 x 10.

Please explain the questions above. Thank you

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Qurton Azy C6 Hts COOH O O CA Ahre, cis the mihal cmuntraton be the dlesmu dimouaton lonzatron conrtan, ka trco0 [6tCoo tHt t10x [eona ptot the sihn nven y Hendersm eneton pka t aH cooH =y 6.4x I0-5) 4.19 thn trom Ne have, SXI03 4-41 4 S optan-tc) Su

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