Question

2. One mole of an ideal gas at an initial state of 300 K, 2.4618 atm and 10.0 L is isothermally expanded to 20.0 L against a constant external pressure of 1.2309 atm. Calculate AU, W, q, and AS for the process. Show that the Clausius inequality is satisfied.

Answer 1

for ideal gas, internal courgy (v) is the hection of temparature non for isothermal frow tematadures force?. tince, dT=0 this from othermal reversible proocess, DU=0. for wother mod reversible prown, expresion of workis givenky, W= nRT in - 11 x 8 314 gest if x 3008 in 20 = 8.314x300 xina J = 7728:15] = 1.73 kJ now from the first law of their dynamics, du - tq + tw. hore, Du=6 - Ag+ dw, -q=-W there, q = - 1073 kJ for ideal gas, changementropy for othermal po prous is gron by Ds=nR in 2 = -ply 8.3145 motikt x ln - 20 = - 57628 JKT closions mequality is given by to do ay for eam prom, 4 for spontaniom froom,

Tds = 300** 15.7628) 764 = -30075-4628 tyd om te 1000 cut 1.73 19 = dq us to = T de this proved clersson megality. & Hone is an equilibrium