Question

solve the blanks

Data and Calculations 1. AH (neutralization & dilution) of 10 M H:SO4 and 1.00 M NaOH Keain Data Trial 1 Trial 2 Initial temperature of 10 M H2SO (5.0 mL in a graduated eylinder) 23.2 23.8 C C Initial temperature of calorimeter (50.0 mL of 1.00 M NaOH 45.0 mL water) 22.8 °C 2 1.5 °C Final temperature of the mixed solutions in calorimeter (50 mL 1.00 M NaOH 45.0 mL water 5.0 mlL 10 M H2SO) २2 १ °c C Trial 2 Calculations Trial 1 (a) Temperature change of NaOH solution in calorimeter 1 (ATC Tfinal -Tinitial) C C4 C to n (b) Temperature change of added H2SO4 solution 4.1 5.7 C C (ATG Tfinal -Tinitial) (e) Calculate the heat gained by the NaOH solution. Assume that the product of density heat capacity (d C) is 4.10 J mL K. AHc J J VedC, A Te (d) Calculate the heat gained by the H2SO4 solution. Assume that the product of density heat capacity J (d C) is 4.10 J. mL. K. AHo -Vad CTo (e) Calculate AHeaction AHreaction-AHc-AH J (f) Calculate the moles of added H2SO4 mol H2SO4 Vo(L) M (mol/L) mol mol (g) Calculate AHcaction per mole of reactants by dividing the results of part I (e) by the number of moles of H2SO4 calculated in part I (f). Express the final result in units of kJ/mol. Be sure to keep the proper sign of the calculated reaction enthalpy kJ/mol kJ/mol kJ/mol Average At 50D 410 Gk Page 103

Answer 1

1. All (neutralization and dilalien) of 10M 11,504 and 1.00m NaOH. TRIAL 1 TRIAL 2 DATA 23.2°C 23.8.0 22.8°C 21.5°C Joitial temperature of som H₂SO4 (5.0ol is a graduated cylinder) Jhal tengerature of Calor inefer 50.0 mL of 1.00m Naal + 45.0ml tho) Final temperature of the mixed Solutions in Cabrioler ISOL IM NAOH, 475 ml.bo, 5mL IOM H501) CALCULATIONS C) Temyweature Change of NaOH Solution in Calorimeter. (ATC = Trinal - Tintil) 28.9 °c 27.9°C TRIAL 1 TRIAL 2 6.1 °C 6.4 °C 5.7 °C 4.1°C 1250.5 J 1312 J b) Temperature Change of added 16504 Schition (OTG = I final - Tinitial) co Calculate the heat gained by the Naoh solution. (ocs = 4.10 Jmollis | Atle=Vc de ATC Kd) Calculate the heat gained by the th, sosolubion. (des= $.logmei 5!) sha= Vo. des. Ata ke) At reaction = - AH. - AHA (6) Moles of added 46504 EVEIL) M (od/L) 10) Stireaction mole of reactante el 116.85 J 84.05 J -1367.35 J -1396.05 J 0.05 mol 0.05 mol (kJ/mal) o - 27.347 KJ/mol -27.921 KI mol Averag -27634kJ/mol.

H₂SO₄(aq) + 2NaOH(aq) --> Na₂SO₄(aq) + 2H₂O(l)            $\Delta$H_neut= -27.63 KJ/mol