Question

A 10.0 g solid sample contains 14.0% NaHCO3 by mass; the rest is NaHSO4. Find the mass of CO2 gas it will produce if treated with an excess of hydrochloric acid. Molar masses: M(NaHCO3) = 84.007 g/mol, M(CO2) = 44.01 g/mol. The gas-evolution reaction:

NaHCO3(s) + HCl(aq) = NaCl(aq) + H2O(l) + CO2(g).

(A) 0.733 g (B) 1.47 g (C) 2.67 g (D) 4.51 g (E) 5.24 g

Answer 1

mans of Nadt coz = 10x it – 1.4 gramy = 1.4 84.007 – 0.0167 Too - moles of Nafto= mann molar maps Nancoz t Hd - Nacht H₂o f og a moles of Co2 = moles of Narco, (look above reaction). 0.0167 maps of coo- mole x molar manx 0.0167 uu - 0.73327 gramy or 0.733 [A]

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