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QUESTION 2 A hospital is offering three cardiac rehabilitation programs that are identical in content but are offered at thre
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Answer #1

1) Ho: three day and time option are equally popular

H1: three day and time option are not equally popular

2) Chi square test for Goodness of fit

3) level of significance, α=   0.05              
Degree of freedom=k-1=   3   -   1   =   2

Critical value =    5.9915   [ Excel function: =chisq.inv.rt(α,df) ]  

reject Ho if test stat >5.9915

4)

expected frequncy,E = expected proportions*total frequency  
total frequency=   100

observed frequencey, O expected proportion expected frequency,E (O-E)²/E
46 0.333 33 4.813
33 0.333 33 0.003
21 0.333 33 4.563

chi square test statistic,X² = Σ(O-E)²/E =   9.3800

5) since, test stat > critical value, reject ho

there is enough evidence that three day and time option are not equally popular

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