The Ksp and Kf values are not given, I think: Kf = 5.0 X 1013
Answer :
3.78*10^-14 M
0.293 M
0.014 M
The Ksp and Kf values are not given, I think: Kf = 5.0 X 1013 If 2.10 g of CusO, is dissolved in 9.21 x 10- mL of 0.350...
Be sure to answer all parts. If 2.10 g of CuSO4 is dissolved in 9.05 x 102 mL of 0.380 M NH3, calculate the concentrations of the following species at equilibrium. Cu2+ 11.8 X L:14 V Enter your answer in scientific notation. NH3 Cu(NH3)42+
Be sure to answer all parts. If 2.10 g of CuSO4 is dissolved in 8.75 × 102 mL of 0.310 M NH3, calculate the concentrations of the following species at equilibrium. Cu2+ × 10 M Enter your answer in scientific notation. NH3 M Cu(NH3)42+ M
If 2.40 g of CuSO4 is dissolved in 8.79 × 102 mL of 0.300 M NH3, calculate the concentrations of the following species at equilibrium. Cu2+ × 10 MEnter your answer in scientific notation. NH3 M Cu(NH3)42+ M
Be sure to answer all parts. If 2.25 g of CuSO4 is dissolved in 9.07 × 102 mL of 0.320 M NH3, calculate the concentrations of the following species at equilibrium. Cu2+ × 10 MEnter your answer in scientific notation. NH3 M Cu(NH3)42+ M
If 2.30 g of CuSO4 is dissolved in 8.65 × 102 mL of 0.330 M NH3, calculate the concentrations of the following species at equilibrium. Cu2+ ___ × 10^__ M Enter your answer in scientific notation. NH3 ___ M Cu(NH3)4^2+ ___ M
For CuCO3, Ksp is 2.5 x 10-10 M2. For CuCl42-, Kf is 5.0 x 105 M-4. What is the value of the equilibrium constant for the sum of the two reactions shown below? CuCO3 ↔ Cu2+ + CO32- Ksp = 2.5 x 10-10 M2 Cu2+ + 4 Cl- ↔ CuCl42- Kf = 5.0 x 105 M-4 CuCO3 + 4 Cl- ↔ CuCl42- + CO32- K = ? K = ___ M-2 Based on the previous problem, what is the maximum...
For CuCO3, Ksp is 2.5 x 10-10 M2. For CuCl42-, Kf is 5.0 x 105 M-4. What is the value of the equilibrium constant for the sum of the two reactions shown below? CuCO3 ↔ Cu2+ + CO32- Ksp = 2.5 x 10-10 M2 Cu2+ + 4 Cl- ↔ CuCl42- Kf = 5.0 x 105 M-4 CuCO3 + 4 Cl- ↔ CuCl42- + CO32- K = ? K = ___ M-2 Based on the previous problem, what...
Please show all work so that it's easy to follow and
understand.
If 2.35 g of Cuso, is dissolved in 0.51 x 102mL of 0.380 M NH3, calculate the concentrations of the following species at equilibrium. x 10M Enter your answer in scientific notation. NH3 Cu(NH3)22+
a. Using the Ksp value for Cu(OH)2 (1.6 x 10-19) and the overall formation constant for Cu(NH3)42+ (1.0 x 1013), calculate the value for the equilibrium constant for the following reaction: Cu(OH)2 (s) + 4NH3 (aq) ⇌ Cu(NH3)42+(aq) + 2OH -(aq) b. Use the value of the equilibrium constant you calculated in part a to calculate the solubility (in mol/L) of Cu(OH)2 in 5.0 M NH3. In 5.0 M NH3 the concentration of OH - is 0.0095 M.
1.Given a solution in which [Cu2+] = 0.20 mol/L and [NH3] = 1.40 mol/L, what is the equilibrium concentration of free Cu2+? The complex Cu(NH3)42+ has Kf = 5.0 X 1013. The answer to the question is 3.1 X 10 -14 I just need how to do it with the work shown. 2. You titrate a 20.00 mL sample of ammonia (Kb = 1.8 X 10-5) to the equivalence point using 10.00 mL of .20 M HCl solution. What is...