Molar mass of KNO3=Molar mass of K+Molar mass of N+3xMolar mass of O=39 g/mol+14 g/mol+3x16 g/mol
=39 g/mol+14 g/mol+48 g/mol
=101 g/mol
Molarity=number of moles/volume of solution (L)
=(Mass of KNO3/Molar mass of KNO3)/(Volume of solution(mL)/1000 mL/L) (1 L=1000 mL)
1.65 M=(Mass of KNO3/101 g/mol)/(750 mL/1000 mL/L)
1.65 M x (750 mL/1000 mL/L)x101 g/mol=Mass of KNO3
So mass of KNO3 required=125 g
please show all steps 3. Calculate the mass in grams, of KNO3(s) needed to make 750 mL of a 1.65 M solution.
Calculate the mass in grams, of KNO3(s) needed to make 750 mL of a 1.65 M. solution.
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