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Check my work Identify the substance being reduced in the unbalanced reaction. K(s) +H2011 — H2(g) + KOH(aq) 0.66 points eBoo

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oxidation state of H is reducing (+1) to (0)....

H2O(l) is reducing in this redox reaction.

oxidation state of k oxidation state of k =0 KOH(as) let oxidation state of k = x x + (-2) + 1 = 0 x -2 +1 =0 x-1=0 1 = + 1 ~

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