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In the laboratory you set up an experiment as shown below. You maintain a constant reservoir so Water inflow that the driving

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Answer #1

Ans) Given,

Diameter of column = 20 cm or 0.20 m

Permeability(K) = 10-4 m/s

a) We know,

Q = K i A

where, i = hydraulic gradient

A = cross sectional area of column

i = h/L = 0.1/0.5 = 0.20

=> Q = 10-4 x 0.20 x (\pi/4) x 0.20 x 0.20

Q = 6.28 x 10-7 m3/s

b) We know,

V = K x i / \eta

where, \eta = porosity

=> V = 10-4 x 0.20 / 0.20

=> V = 10-4 m/s

Time taken to flow 50 cm or 0.50 m = 0.50 / 10-4 sec

= 5000 sec or 83.33 min or 1.38 hour

c) According to Flick's law,

N = D x C

N = 10-4 x 0.10 = 10-5 mol m2/s

t = CA /N

= 0.01 x (0.785 x 0.2 x 0.2) / 10-5

= 31.4 sec

d) New time = t x chemical retardation factor

= 31.4 x 5

= 157 sec

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