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question 9,10
Page 5 of 6 9. Scott collected 6.60 L of methane at 745 torr and 25 °C, which weighed 4.24 a) (2 pts) Convert the pressure to
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Answer #1

given
pressure of methane = 745 torr =0.980263 atm
Temperature T = 25 C = 273 K + 25 = 298 K

volume of gas = 6.60 l
we have gas constant R = 0.0821 latm/mol/k

use gas equation PV= nRT

let us find out number of moles of methane present

n = PV/RT =0.980263 atm*6.60 l/[0.0821 latm/mol/k*298 K]

n= 0.2644 mols

Molar mass = Given mass of methane/number of mols of Methane present
= 4.24 g/0.2644 mols = 16.03 g/mols
*******************************************************

gas law

constant

variables

mathematical

description

description
Boyles Law Temperature,number of moles P = constant/V

As pressure increases

volume decreases

Charle's Law Pressure,number of mols V= constant*T As temperature increases volume increases
Gay-Lussac's law volume ,number of mols P=constant*T

As temperature increases

pressure increases

Avogadro's Law pressure, temperature V=constant*n Equal volume of gases at same pressure and temperature contain same number of molecules

All solved. Kindly upvote

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