Question

Balance the following chemical equation. What are the correct stoichiometric coefficients for each molecule, in the order they appear in the reaction? Na, PO, NICI, --> NI,(PO), + Naci Select one: a. 2; 3; 1; 3 b. 1; 3; 1: c. 2; 3; 2: 1 d. 2; 3; 1; 6

Answer 1

The reaction is:

L.H.S. R.H.S.

Na3PO4 + NiCl2 --> Ni3(PO4)2 + NaCl

L.H.S= LEFT HAND SIDE

R.H.S= RIGHT HAND SIDE

To balance this reaction,

First look at the main elements Ni and PO4.

Ni is 3 at R.H.S. so first we will write 3 with NiCl2 right.

So, equation will be,

Na3PO4 + 3 NiCl2 = Ni3 (PO4)2 + NaCl

So nickel element is balanced.

​​​​​​Now, PO4 is 2 at R.H.S, so we need to add 2 with Na2PO4 to balance PO4,so equation will be

2Na3PO4 + 3 NiCl2 = Ni3 (PO4)2 + NaCl

Now look at Na and Cl,

Na is 2×3 = 6 at L.H.S and 1 at R.H.S,

Cl is 3 × 2 = 6 at L.H.S and 1 at R.H.S

so, we need to add 6 with NaCl to balanced these elements.and there is no change with Ni3 (PO4)2 ,so will write 1 with it.

Our final balanced equation will be,

2 Na3PO4 + 3 NiCl2 --> 1 Ni3(PO4)2 + 6 Nacl

As you can see the coefficients in bold numericals .

The correct sequence Wii be,

2 , 3 , 1, 6

Our answer match with option ""d"".

Correct answer is: d. 2; 3; 1; 6.

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