Homework Answers
1) Molar mass of KHC8H8O4 = 208.25 g/mol
Molar mass of KOH = 56.10 g/mol
According to the reaction,
208.25 g KHC8H8O4 react with 56.10 g KOH
0.400 g KHC8H8O4 react with 56.10×0.4/208.25 g KOH
= 0.1077 g KOH
Molarity of KOH = mass×1000/molar mass×volume(ml)
= 0.1077×1000/56.10×16.58 M
= 0.1158 M
2) According to the reaction,
1 mole H2SO4 require 2 mole KOH
Thus, M1V1 (H2SO4) = 2× M2V2(KOH)
M1×10 = 2×0.1158×12.97
M1 = 0.3005 M
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I need help with question #1 and 2 under Post Lab
based on the Data Table 1. I appreciate the help.
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