Reactant side we have:
4 C-H bonds
4 Cl-Cl bonds
Product side we have:
4 C-Cl bonds
4 H-Cl bonds
Use:
delta H = BE(reactant) - BE(product)
= 4*BE(C-H) + 4*BE(Cl-Cl) - 4*BE(C-Cl) - 4*BE(H-Cl)
= 4*414 + 4*243 - 4*331 - 4*431
= -420 KJ
Answer: -420 KJ
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