P = 1.0atm
T= 0.0 oC
= (0.0+273) K
= 273 K
Molar mass of SF4,
MM = 1*MM(S) + 4*MM(F)
= 1*32.07 + 4*19.0
= 108.07 g/mol
Lets derive the equation to be used
use:
p*V=n*R*T
p*V=(mass/molar mass)*R*T
p*molar mass=(mass/V)*R*T
p*molar mass=density*R*T
Put Values:
1 atm *108.07 g/mol = density * 0.08206 atm.L/mol.K *273.0 K
density = 4.824 g/L
Answer: 4.82 g/L
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