A torque of 0.97 NM is applied to a bicycle wheel of radius 45 cm and mass 0.80 kg. Treating the wheel as a hoop, find...

Question

Question

A torque of 0.97 NM is applied to a bicycle wheel of radius 45 cm and mass 0.80 kg.
Treating the wheel as a hoop, find its angular acceleration.

Answer 1

Answer #1

τ = mr^2α

α = τ/mr^2 = 0.97/(0.8*0.45^2) = 5.988 rad/s^2

Answer 2

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