Question

Exercise 28.6

Positive point charges q = 7.00 ?C and q?= 4.00 ?C are moving relative to an observer at point P, as shown in the figure (Figure 1) . The distance d is 0.130 m , v = 4.40×10⁶ m/s , and v?= 8.80×10⁶ m/s .

Part H

If the direction of v? ? is reversed, so both charges are moving in the same direction, what is the magnitude of the magnetic forces that the two charges exert on each other?

F_B=_____N

Answer 1

Part H The distance between the charges is r d+d 2d 2(0.130 m) 0.26 nm force acting between them is F-o magnitude of the ma Here, the two charges exert same magnetic force on each other. Now, we have (7x10 C)(4x10 C)(4.4x10 m/s) (8.8x10 m/s) (0.26 m) F-10 -16037.9x10 N 1.60379 10-3