Question

1. What mass (in g) of Na2Cr2O7 is required to make 500.0 mL of a 2.0 M solution?

Answer 1

molar man of = 262 g wel of Na - 139, er = 529, 018g molecule Molar mass = { sum of aloms present in the molar mass = non mass of Nar mass of er mass of o of Nazcrgo7 - (23x2 + 52X2 + 16x?), : (46+1047 112) Ny cool dod g we know - 1 more of any substance = Gram molecular mass . Imole of Na, C907 weighs - 2629 : By definition of molarity, 1000 ml IM Na, cnog will contain = I moles 1 ml IM Na, Cro will contain - I moles. 500 ml IM Nazaroor will contain - 500 / moles 1000 POOD2 500 ml OM NA₂C2O7 will contain = 0.5x2 moles 10.8 moles - mole: 30, 500 me am Na, croz contain Neighs 1262 gm] Any a mole of Nazing of which Scanned with CamScanner