If a charge is located at the center of a spherical volume and the electric flux through the surface of the sphere is...
Gauss's law may be expressed as:
where ?E is the electric flux through a closed surface S enclosing any volume V, Q is the total charge enclosed within S, and ?0 is the electric constant.
Now , as the charge inside the sphere is not changed by changing it's radius
therefore , the flux remains same as before = phi
OPTION(5) phi is the correct choice
If a charge is located at the center of a spherical volume and the electric flux through the surface of the sphere is.....
If a charge is located at the center of a spherical volume and the electric flux through the surface of the sphere is Φ, what would be the flux through the surface if the radius of the sphere were tripled? 1) theta/9 2) 3theta 3) 9theta 4) theta 5) theta/3
If a charge is located at the center of a spherical volume and the electric flux through the surface of the sphere is Φ, what should be the flux through the surface if the radius of the sphere were tripled? Draw the diagram with a sphere of radius R and the second surface of radius 3R. Draw enough field lines to illustrate the field. Calculate the flux through each surface. What is the relationship of the flux through radius R...
18a) Find the flux through the whole surface of the sphere. b) Find the magnitude and direction of E at the surface.1 Now put the same charge at the center of a spherical shell- with twice the diameter. c) Find the magnityde and direction of E at the surface.1 d) Find the flux through the whole surface of the sphere.1 e) Why is the flux the same, even though E is weaker?1 18, A particle with charge of 12.0 μC...
what is the total electric flux due to these two point charges through a spherical surface centered at the origin and with radius r 1 = 0.610 m ? Constants A point charge q.-3.95 nC is located on the x-axis at z 2.25 m, and a second point charge g2--5.50 C is on the y-axis at y 1.25 m Submit Request Answer ▼ Part B What is the total electric flux due to these two point charges through a spherical...
4. a- A Gaussian sphere with radius 1.20 m encloses a point charge Q1 = 2.20×10–6 C at the spherical center. The electric flux through the spherical surface is measured to be 1. Now Q1 is removed, and another point charge Q2 = –8.80×10–6 C is placed at the spherical center. The electric flux through the spherical surface is then measured to be 2. What is 2/1? b- A Gaussian sphere with radius 1.20 m encloses a point charge Q1...
A point charge causes an electric flux of -1000 N-m2/C to pass through a spherical Gaussian surface of 10.7 cm radius centered on the charge. (a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface? (b) What is the value of the point charge in coulombs?
A point charge of 5.1 μC is located at the center of a sphere with a radius of 7 cm. The Coulomb constant is 8.98755 × 109 Nm2/C2, and the acceleration of gravity is 9.8 m/s2. Determine the electric flux through the surface of the sphere. Answer in units of N/C.
Three point charges are located near a spherical Gaussian surface of radius 12.5 cm. One charge (+3Q =11.4 μC) is inside the sphere, and the others (charge +Q =3.8 μC) are a distance 4.16666666666667 cm outside the surface. What is the total (net) electric flux through the Gaussian surface?
A positive point charge is placed at the center of an imaginary spherical surface. As a result, there is some total electric flux outward through the surface. For each of the changes listed below, how would the total outward flux though the surface change? The total flux increases The total flux decreases The total flux is unchanged a negative charge is placed the charge is moved off-center a positive charge is placed just outside the surface by an amount equal...
A point charge is located in the center of a spherical Gaussian surface. Changes ΦE (a) if the surface is replaced by a cube of the same volume, (b) if the sphere is replaced by a cube of one tenth of the volume, (c) if the load moves outside the center of the original sphere and stays inside, (d) if the load moves just outside the original sphere, (e) if a second charge is placed near and outside the original...