Question

What are the concentration of the ions if 1.0 moles Al₂(CO₃)₃ is dissolved in 0.50 L of solution?

		[Al3+] = 4.0 M              [CO32-]= 6.0 M
		[Al3+] = 2.0 M              [CO32-] = 3.0 M
		[Al3+]= 1.5 M             [CO32-]= 1.5 M
		[Al3+] = 12 M            [CO32-] = 18 M

Answer 1

Answer:

Step 1: Calculate the Molarity (concentration) of a Al₂(CO₃)₃

we know, Molarity = moles / volume (in L ) = 1 moles / 0.5 L = 2 M

Step 2: Calculation

The dissolution equation for Al₂(CO₃)₃ in aqueous solution is:

Al₂(CO₃)₃--------------> 2 Al⁺³ + 3 CO^-2₃

Thus, every mole of Al₂(CO₃)₃ dissolves into 2 moles of Al⁺³   and 3 mole of CO^-2₃

If the original concentration of   Al₂(CO₃)₃ is 2 M, then

[Al⁺³] = 2×2 M = 4 M

[ CO^-2₃] = 3×2 M = 6 M

Hence, option(b)