What is the pH of a solution that is 0.456 M in diethylamine (CH3CH2)2NH and 0.547 M in diethylamine chloride (CH3CH2)2NH2Cl?
The Kb for diethylamine is 6.9 x 10-4.
pKb = - logKb
pKb = - log( 6.9 ×10-4) = 3.16
pKa = 14 - pKb
pKa of (CH3CH2)2NH2+ = 14 - 3.16 = 10.84
Henderson - Hasselbalch equation which gives pH of a buffer solution
pH = pKa + log([A-]/[HA])
pH = 10.84 + log ( 0.456M/0.547M)
pH = 10.84 - 0.08
pH = 10.76
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